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john Guest
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Posted: Wed May 09, 2007 11:37 am Post subject: question from ap chem |
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a samle problem from ap chem handout.
2 SO2 (g) + O2 (g) -> 2 SO3(g)
A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a
4.0 L flask reacts to form SO3. If the tempertaure is 25C. what is
the pressure in the flask after reaction is complete?
answer. ( 0.3 (0.082) (298) ) / 4 atm
but it seems to me the answer shoudl be
( 0.4 (0.082) (298) ) / 4 atm
since P = ( n1 + n2 )( RT/V )
= (0.2 + 0.2 )( RT/V )
Thanks for any input. |
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Uncle Al Guest
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Posted: Wed May 09, 2007 8:05 pm Post subject: Re: question from ap chem |
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john wrote:
| Quote: |
a samle problem from ap chem handout.
2 SO2 (g) + O2 (g) -> 2 SO3(g)
A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a
4.0 L flask reacts to form SO3. If the tempertaure is 25C. what is
the pressure in the flask after reaction is complete?
answer. ( 0.3 (0.082) (298) ) / 4 atm
but it seems to me the answer shoudl be
( 0.4 (0.082) (298) ) / 4 atm
since P = ( n1 + n2 )( RT/V )
= (0.2 + 0.2 )( RT/V )
Thanks for any input.
|
Look at the stoichiometry. 0.2 mol SO2 will react with 0.1 mole of
O2. You don't need any RT/V diddles - it cancels. (0.2 mol + 0.1)
mole reactants --> 0.2 mol product plus 0.1 mol background unchanged.
Wrote procedure is good, so is understanding what you are doing. Do
not look at the trees to the exclusion of the forest - or you get
Canadian mangement of the Grand Banks fishery (utter destruction for
the nicest of possible reasons, with voluminous punctilious
documentation to the contrary until physical reality voted).
--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2 |
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Angelo Guest
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Posted: Wed May 09, 2007 8:24 pm Post subject: Re: question from ap chem |
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On 9 Mag, 08:37, john <johnboy98...@yahoo.com> wrote:
| Quote: |
a samle problem from ap chem handout.
2 SO2 (g) + O2 (g) -> 2 SO3(g)
A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a
4.0 L flask reacts to form SO3. If the tempertaure is 25C. what is
the pressure in the flask after reaction is complete?
answer. ( 0.3 (0.082) (298) ) / 4 atm
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In that answer, as well below, there should be a typo:
P = ( 0.3 (0.082) (298) ) / 4 L
Having a fixed volume V and a fixed temp T, what
makes up the pressure? Is there a limiting reactant,
or IOW, is there a reactant that remains unchanged?
Keep also in mind that in a chemical reaction
there's no law of mole conservation.
| Quote: |
but it seems to me the answer shoudl be
( 0.4 (0.082) (298) ) / 4 atm
since P = ( n1 + n2 )( RT/V )
= (0.2 + 0.2 )( RT/V )
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That would be the P *before* the beginning
of the reaction (!)
| Quote: |
Thanks for any input.
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Ciao, Angelo |
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