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question from ap chem

 
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john
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PostPosted: Wed May 09, 2007 11:37 am    Post subject: question from ap chem Reply with quote

a samle problem from ap chem handout.

2 SO2 (g) + O2 (g) -> 2 SO3(g)

A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a
4.0 L flask reacts to form SO3. If the tempertaure is 25C. what is
the pressure in the flask after reaction is complete?

answer. ( 0.3 (0.082) (298) ) / 4 atm

but it seems to me the answer shoudl be

( 0.4 (0.082) (298) ) / 4 atm

since P = ( n1 + n2 )( RT/V )

= (0.2 + 0.2 )( RT/V )

Thanks for any input.
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Uncle Al
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PostPosted: Wed May 09, 2007 8:05 pm    Post subject: Re: question from ap chem Reply with quote

john wrote:
Quote:

a samle problem from ap chem handout.

2 SO2 (g) + O2 (g) -> 2 SO3(g)

A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a
4.0 L flask reacts to form SO3. If the tempertaure is 25C. what is
the pressure in the flask after reaction is complete?

answer. ( 0.3 (0.082) (298) ) / 4 atm

but it seems to me the answer shoudl be

( 0.4 (0.082) (298) ) / 4 atm

since P = ( n1 + n2 )( RT/V )

= (0.2 + 0.2 )( RT/V )

Thanks for any input.

Look at the stoichiometry. 0.2 mol SO2 will react with 0.1 mole of
O2. You don't need any RT/V diddles - it cancels. (0.2 mol + 0.1)
mole reactants --> 0.2 mol product plus 0.1 mol background unchanged.

Wrote procedure is good, so is understanding what you are doing. Do
not look at the trees to the exclusion of the forest - or you get
Canadian mangement of the Grand Banks fishery (utter destruction for
the nicest of possible reasons, with voluminous punctilious
documentation to the contrary until physical reality voted).

--
Uncle Al
http://www.mazepath.com/uncleal/
(Toxic URL! Unsafe for children and most mammals)
http://www.mazepath.com/uncleal/lajos.htm#a2
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Angelo
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PostPosted: Wed May 09, 2007 8:24 pm    Post subject: Re: question from ap chem Reply with quote

On 9 Mag, 08:37, john <johnboy98...@yahoo.com> wrote:
Quote:
a samle problem from ap chem handout.

2 SO2 (g) + O2 (g) -> 2 SO3(g)

A mixture of gases containing 0.20 mol of SO2 and 0.20 mol of O2 in a
4.0 L flask reacts to form SO3. If the tempertaure is 25C. what is
the pressure in the flask after reaction is complete?

answer. ( 0.3 (0.082) (298) ) / 4 atm

In that answer, as well below, there should be a typo:

P = ( 0.3 (0.082) (298) ) / 4 L

Having a fixed volume V and a fixed temp T, what
makes up the pressure? Is there a limiting reactant,
or IOW, is there a reactant that remains unchanged?
Keep also in mind that in a chemical reaction
there's no law of mole conservation.

Quote:
but it seems to me the answer shoudl be

( 0.4 (0.082) (298) ) / 4 atm

since P = ( n1 + n2 )( RT/V )

= (0.2 + 0.2 )( RT/V )

That would be the P *before* the beginning
of the reaction (!)

Quote:
Thanks for any input.

Ciao, Angelo
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